Daily Chess Puzzle November 02, 2014

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Hanley,Craig (2387) – Harikrishna,Penteala (2558)
BCF-ch Edinburgh (1), 14.07.2003
Ruy Lopez Breyer Variation [C95]

1.e4 e5 2.Nf3 Nc6 3.Bb5 a6 4.Ba4 Nf6 5.0-0 Be7 6.Re1 b5 7.Bb3 d6 8.c3 0-0 9.h3 Nb8 10.d4 Nbd7 11.Nbd2 Bb7 12.Bc2 Re8 13.Nf1 Bf8 14.Ng3 g6 15.b3 Bg7 16.d5 Qe7 17.c4 c6 18.Rb1 Rec8 19.Be3 a5 20.Bd3 bxc4 21.bxc4 Ba6 22.Re2 Nc5 23.Bxc5 dxc5 24.Rc2 cxd5 25.cxd5 c4 26.Bf1 Ne8 27.Rb6 Nd6 28.Nd2 Bh6 29.Qb1 Qd8 30.Be2 Rcb8 31.Rxb8 Rxb8 32.Qa1 Nb5 33.Qxe5 Na3 34.Rb2 Rc8 35.Qd4 Nb5 36.Rxb5 Bxb5 37.Nxc4 Bg7

How should Black respond to 38.e5?

38…Bxc4 39.Bxc4 Qc7 40.Bb3 Bxe5 41.Qg4 h5 42.Qe4 Bxg3 0-1